This touching story took place on a rainy day when a hostess named Monica took her adorable dog Hazel out for a walk. They calmly walked, but then the baby noticed a tiny kitten …
In the next moment, Monica did not even believe what she saw with her own eyes. Hazel began to run next to a small creature that did not know where to go from the downpour.
As if sensing that they wanted to help him, the kitten followed the dog and began to follow on his heels. If the baby lagged behind, Hazel stopped and waited for him to approach. Together they walked around a large puddle and again ran together.
At first, Monica thought that they would say goodbye and the kitten would go on her way, but no such luck! The animals traveled all the way home together, and near a huge puddle, Hazel helped the baby to climb onto the curb.
But then it got even more interesting! Monica hoped that the dog and kitten would definitely say goodbye at the door, but Hazel turned and watched the kitten climb up. The baby was too small for the threshold, so he rolled down. And then the dog ran up to him, grabbed his withers with his teeth and pulled him straight to the house! And the next moment the baby ran after her into the hallway!
Monica didn’t know what to think, but she couldn’t kick the little kitten out. Hazel’s behavior simply shocked her: the dog made sure that the homeless baby did not sit in the rain! And if so, then, being a person with a kind heart,
Monica simply cannot do cruel things to a kitten! That is why the hostess sheltered the baby, who, by the way, turned out to be a “girl”. The baby was named Sheba, and soon Monica’s brother took her to his house. There the purr lives very well!
Well, we can only admire the kindness of the dog that saved the kitten from the rain!
