Animals are very kind to their babies and try to protect them from all dangers. To help their children and save them, animals are capable of truly heroic deeds. A dog named Snoubbel is one of those who, for the sake of their babies, risked their own lives. It was very cold outside, but the dog did not look for a warm place, she stayed next to her puppies and warmed them with her body, although she herself suffered greatly from the cold.
This mother dog and her babies were found in the snow in Minnesota. The winter in this state is very severe, and the dog and her six puppies caught her on the street. When people found this family, they immediately took the animals to a local shelter.
The veterinarian examined the puppies and came to the conclusion that they were about three weeks old, all this time they lived on the street, despite the severe frosts. Probably, Snoubbel began to give birth during a snowstorm, so she could not move the babies anywhere, but she did not want to leave them either.
An examination of her mother showed that life in the cold and half-starving deprived her of milk, but as soon as Senoubbel warmed up and ate, she was again ready to feed her kids. Snowbell is considered a real heroine in the shelter, because she herself did not hide from the cold, but took care of her kids. When the puppies grew up, for each of them the staff of the shelter found a new home and loving owners.
